
This article explains solving linear simultaneous equations using the elimination and substitution methods, with examples. LearnPick connects students to experienced tutors for personalized help in mastering these concepts effectively.
Linear simultaneous equations are a set of equations with two or more variables. When we have two equations with two variables, it is called a system of linear equations. Solutions of linear simultaneous equations are the values of the variables that satisfy all the equations in the system.
The elimination method involves adding or subtracting equations to eliminate one variable. Here's an example to illustrate the elimination method:
Solve the following system of linear equations using the elimination method:
2x + 3y = 10
4x - 5y = -6
Step 1: Multiply one or both equations by a constant to make the coefficients of one variable same in both of the equation.
Multiply the first equation by 2 to make the coefficient of x is 4.
4x + 6y = 20
4x - 5y = -6
Step 2: Now subtract the equation second from First to eliminate one variable.
4x + 6y - 4x - (-5y) = 20 - (-6)
11y = 26
y = 26/11
Step 3: Substitute the value of y into one of the original equations to find the value of x.
2x + 3(26/11) = 10
2x + 78/11 = 10
22x + 78 = 110
22x = 32
x = 16/11
Therefore, the solution to the system of equations is (x, y) = (16/11, 26/11)
The substitution method involves solving one equation for one variable and substituting the resulting expression into the other equation(s). Here's an example to illustrate the substitution method:
Solve the simultaneous equations below using the substitution method:
2x + 3y = 10
4x - 5y = -6
Solving the first equation for x, we get:
x = (10 - 3y)/2
Substituting this expression for x into the second equation, we get:
4(10 - 3y)/2 - 5y = -6
20 - 6y - 5y = -6
11y = 26
y = 26/11
Substituting this value of y into the first equation, we get:
2x + 3(26/11) = 10
2x + 78/11 = 10
22x + 78 = 110
22x = 32
x = 16/11
Therefore, the solutions of the system are x = 16/11 and y = 26/11.
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